Question

a train moving with a velocity of 108km\h decelerates at the rate of 0.2m\s and stops in 5mins. find the distance travelled after braking

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Answer 1

Answer: 75 m

Explanation:

S = u^2/2a

= 30^2/2×6= 75 m

Answer 2

Explanation:

First we will need to convert everything in to m/s

speed of train

108km/h---->m/s

108*5/18

=16*5

=80m/s

Retardation of train

0.2m/s²

Time

5min

5*60

300sec

So

u=80m/s

a=-0.2m/s²

t=300sec

To find s

s=ut+(1/2)at²

s=80*300+(1/2)(-0.2)300²

s=24000-0.1*90000

s=24000-9000

s=15000m

Thank you

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