Question

a train start from rest position and moving with uniform accleration attains a speed of 36 km per hour in 10 min . find its accletation

Answer 1

Initail velocity(u) = 36 * 5 / 18 = 10 m/s
time = 10 min = 600 sec

Equation of motion
$v=u+at \\ 10=0+a(600) = 0.0166 m/s^2$

Answer 2

Explanation:

$Initail velocity(u) = 36 * 5 / 18 = 10 m/s</p><p>time = 10 min = 600 sec</p><p></p><p>Equation of motion</p><p>\begin{gathered}v=u+at \\ 10=0+a(600) = 0.0166 m/s^2\end{gathered}v=u+at10=0+a(600)=0.0166m/s2</p><p>$