Question

A train starting from a railway station and moving with uniform acceleration attains a speed 40km/h in 10 minutes. Find its acceleration.

Answer 1

Answer:

Known Terms:-

u = Initial speed

v = Final speed

a = Acceleration

t = Time

Given:-

Initial speed of the train, u = 0 km (Because train starts from the rest.

Final speed of the train, v = 40 km/h = $\frac{5}{18}$ × 40 = 11.11 m/s.

Time taken to attain the speed = 10 minutes = 10 × 60 = 600 sec.

To Calculate:-

Acceleration of the train.

Formula to be used:-

⇒ $a=\frac{v-u}{t}$

Solution:-

Putting all the values, we get

⇒ $a=\frac{v-u}{t}$

⇒ $a=\frac{11.11-0}{600}$

⇒ $a=\frac{11.11}{600}$

⇒ $a=0.0185 \: m/s^2$

Hence, Acceleration of the train is 0.0185 m/s².

Answer 2

Answer: The acceleration of the train is 0.0185 m/sec².

Explanation:

The acceleration of a body is the rate of change of velocity with respect to time.

Let, the initial velocity of a body be u and the final velocity of the body be v.

Then, acceleration of the body is

$a=\frac{v-u}{t}$

S.I. unit of acceleration is m/sec².

Here, initial velocity, u = 0 Km/hrs.

Final velocity, v = 40 Km/hrs = $\frac{(40 \times 5)}{18} = \frac{100}{9}$ m/sec

Time taken by train, t = 10 min = 10 x 60 sec = 600 sec.

The acceleration of the train is

$a = \frac{\frac{100}{9} }{600}$

$a =\frac{1}{54}$

$a = 0.0185$ m/sec A²

Hence, the acceleration of the train is 0.0185 m/sec².

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