a train starting from rest attains a speed of 72 km/hr in 5 minutes find the accleration and the distance travelled by the train
vishalsaini:
distance 21600 and acceleration is 0.24
Answers
Answered by
0
Given,. Speed=72 km/hr. Time=5 minutes. Acceleration=? Acceleration= Speed/Time. = 72/5 = 14.4 is your right answer.
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Answered by
1
U=0
V=72*5/18=20m/s
T=5min=300sec
A=v-u/t
A=20-0/300
A=0.06m/s
S=ut+1/2at^2
S=0+2700
S=2700m
V=72*5/18=20m/s
T=5min=300sec
A=v-u/t
A=20-0/300
A=0.06m/s
S=ut+1/2at^2
S=0+2700
S=2700m
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