Question

a train starting from rest moves with a uniform acceleration of 0.2 M per second square for 5 minutes calculate the speed acquired and distance travel in this time.

Answer 1

velocity = acceleration × time =0.2×5×60= 60m/s therefore, velocity 60m/s. distance= ut +1/2at^2 = 0×t+1/2×0.2×300×300=9000m therefore distance = 9km ans