Question

A train starting from rest moving with an uniform acceleration of 0.2m/s^2 in 300 seconds. Calculate the speed aquired and distance travelled

Answer 1

Answer:-

v = 60 m/s

S = 9 km

Given :-

a = 0.2 m/s²

t = 300 s

u = 0 m/s

To find :-

The speed acquired.

The distance travelled.

Solution :-

Let the speed acquired be v,

Since, acceleration is constant so we can use the equation of motion.

★ $\boxed{\sf{ v = u + at}}$

put the given value,

→$v = 0 + 0.2 \times 300$

→$v = \dfrac {2}{10}\times 300$

→$v = 60 m/s$

Now, distance travelled is given by :-

★ $\boxed{\sf{2as = v^2 - u^2}}$

→$2\times 0.2 \times s = (60) ^2 -(0) ^2$

→$0.4 \times s = 3600$

→$s = \dfrac {3600}{0.4}$

→$s = \dfrac {36000}{4}$

→$s = 9000 m, 9 km$

hence,

Distance travelled will be 9 km.