a train starting from stationary position and moving with uniform accelaration attains a speed of 36km/hr in 10 min . find its accelaration and distance travelled during this time. guys i need answer with explanation. pls help me
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Answer:
a train starts from stationary position then initial velocity of train = 0
moving uniform acceleration means constant acceleration .
given ,
final velocity ( V) = 36 km/h = 36× 5/18
= 10m/s
time taken = 10 minutes = 10× 60sec
= 600sec
use kinematics equation ,
V = u + at
10 = 0 + a × 600
a = 10/600 = 1/60 m/s²
a = 0.1667 × 10^-1 m/s² = 1.67 × 10^-2 m/s²
Answered by
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Answer:
initial velocity is 0
acceleration =0+36*6(10 min=1/6 hr
reciprocal of 1/6 is 6)
acceleration=216
distance =avg speed /time
=(36-0)*6. (")
=216 km
=21600 m
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