a train starts from rest and accelerates uniformly at the rate of 2 square for 10 seconds and maintains a constant velocity of 40 second applying the train is uniformly at and stops in 20 second calculate the average velocity of the train
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Answer:
average velocity = total distance/total time
= 2200/70 =31.4m/s
Explanation: Area under a velocity-time graph = Displacement/Distance
total displacement = 2200 m (you need to draw a graph)
total time = 10+40+20 = 70secs
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