Question

A train starts from rest and attains a speed of 54 km /h in 10 seconds. Calculate the acceleration and distance covered by the train

Answer 1

u=0
intial velocity

v=54km/v=54*1000/3600=3000/200=15m/sec

v=u+at
15=0+a*10
a=1.5m/sec2

for distance
v^2=u^2+2as
15^2=0+2*1.5*s

225=3s
s=75m