a train travelling at 20 m/s accelerates at 0.5 m/s2 ( 0.5 metres per second square ) for 30 s. How far will it travel in this time?
Answers
Answered by
636
u = 20 m/s
a = 0.5 m/s²
t = 30 sec
From 2nd equation,
s = ut +(1/2) at²
= 20×30 + (1/2)×0.5×(30)²
= 825 m
a = 0.5 m/s²
t = 30 sec
From 2nd equation,
s = ut +(1/2) at²
= 20×30 + (1/2)×0.5×(30)²
= 825 m
Answered by
330
Solutions
We know that a train travelling at 20 m/s accelerates at 0.5 m/s^2 ( 0.5 meters per second square ) for 30 s.
We have
u = 20 m/s
a = 0.5 m/s²
t = 30 sec
Solve (calculations)
s = ut +(1/2) at^²
= 20×30 + (1/2)×0.5×(30)^²
= 825 m
We know that a train travelling at 20 m/s accelerates at 0.5 m/s^2 ( 0.5 meters per second square ) for 30 s.
We have
u = 20 m/s
a = 0.5 m/s²
t = 30 sec
Solve (calculations)
s = ut +(1/2) at^²
= 20×30 + (1/2)×0.5×(30)^²
= 825 m
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