a train travelling at 20 metre per second accelerates at 0.5 metre per second for 30 seconds how far will it travel in this time
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Explanation:
You can directly use second equation of motion in this case as
S. =. ut +1/2at^2
= 20×30 + 1/2 × 0.5 ×(30)^2
=. 600 + 225 m
= 825 m
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