A train travels a distance of 300 km with uniform speed. If it's speed is decreased by 5km/h. It would have taken 2 hours more to cover the same distance. Find the speed of the train.
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Answered by
0
use, s=d/t
or
speed= distance/time
we have, the speed is 5km/h
but is decreases the speed
so it would be x-5 km/h
apply the formula of s=d/t
x-5= 300/2
x-5= 150
x= 150+5
x=155
Now, The speed of the train is 155 m/s.
or
speed= distance/time
we have, the speed is 5km/h
but is decreases the speed
so it would be x-5 km/h
apply the formula of s=d/t
x-5= 300/2
x-5= 150
x= 150+5
x=155
Now, The speed of the train is 155 m/s.
loviaeb:
I expected the problem to be solved by solving a quadratic equation It's math kavya
so, why uh didn't solve this question by yourself
But according to me, it would be the right answer
No problem if you don't know the answer...I didn't urge you to solve 'em I hope somebody else will answer this the right way and don't get angry , you are still good
✌✌
Answered by
1
Answer:
Let the original speed of the train be y km / hr .
A.T.Q.
300 ( y + 5 ) - 300 y = 2 y ( y + 5 )
y² + 5 y - 750 = 0
y² + 30 y - 25 y - 750 = 0
( y + 30 ( y -25 ) = 0
y = - 30 or y = 25
Since , speed of train can't be negative .
Therefore , the original speed of the train is 25 km / hr .
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