A transparent cube of side d, made of a material of refractive index μ₂, is immersed in a liquid of refractive index μ₁(μ₁ < μ₂). A ray is incident on the face AB at an angle q(shown in the figure). Total internal reflection takes place at point E on the face BC. The q must satisfy : (A) θ > sin⁻¹(μ₁/μ₂)
(B) θ > sin⁻¹√(μ₂²/μ₁² – 1)
(C) θ < sin⁻¹(μ₁/μ₂)
(D) θ < sin⁻¹√(μ₂²/μ₁² – 1)
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Answer:
option B...........................
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Thus the value of angle θ = sin^-1 √μ2^2 / μ1^2
Option (D) is correct.
Explanation:
Sin c = m μ1 / μ2
μ1 sinθ = μ2 sin (90° - C)
Sin θ = μ2 √ 1 - μ1^2 / μ2^2 / μ1
θ = sin^-1 √μ2^2 - μ1^2 / μ1^2
θ = sin^-1 √μ2^2 / √μ1^2
Thus the value of angle θ = sin^-1 √μ2^2 / μ1^2
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