A triangle abc ab=bc=ca the radius of the inner circum circle
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the radius of the circum circle is half the triangle's median
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in the triangle ab=bc=ca so it is an equalateral triangle.
let the side be x
then the radius of the inner circle=half of the median
height is the median in the equilateral triangle
1/2 of the height=1/2*x√3/2=x√3/4
let the side be x
then the radius of the inner circle=half of the median
height is the median in the equilateral triangle
1/2 of the height=1/2*x√3/2=x√3/4
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