Question

A triangle has a perimeter of 49cm. If the three sides of the triangle are n, 3n+5, and 3n+2, what is the length of each side?

Answer 1

Step-by-step explanation:

peeimeter of the triangle is 49cm

sides n , 3n+5 , 3n+2

so,

n+3n+5+3n+2 = 49

7n + 7 = 49

7n = 49–7

7n = 42

n = 42/7

n = 6

therefore length of each side

n = 6 ( 1st side )

3n+5

3(6) + 5

= 18+5

= 23 (2nd side)

3n+2

3(6)+2

= 18+2

= 20 (3rd side)

Answer 2

Answer:

The length of each side is = 6 cm, 23 cm, 20 cm

Step-by-step explanation:

The sum of sides of triangle = perimeter of triangle

49 = n + 3n + 5 + 3n + 2

49 = 7n + 7

49 - 7 = 7n

42 = 7n

6 = n

The first side is = n = 6 cm

the second side = 3n + 5 = 18 + 5 = 23 cm

the third side = 3n + 2 = 18 + 2 = 20 cm

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