Math, asked by armaangoraya2037, 1 year ago

A triangle has sides of lengths 56cm,60cm,and 52cm.Find its perimeter and area.

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Answered by AryanTennyson

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Answered by vikashkumar620

$perimeter \: \ = 56 + 60 + 52 = 168cm \\so \: s = \frac{168}{2} = 84 \\ area = \sqrt{84(84 - 56)(84 - 60)(84 - 52)} \\ = \sqrt{84 \times 28 \times 24 \times 32} \\ = 12 \times 7 \times16<br />=1344 cm2$

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