A trolley of mass 5 kg on a horizontal smooth surface is pulled by a load of 2kg through a uniform rope ABC of length 2 m and mass 1 kg.as the rope falls from BC=0 m to BC=2 m ,its acceleration changes from, (a)20/6 to 30/6 (b)20/8 to 30/8 (c)20/5 to 30/6 (d)None of These
Answers
The acceleration changes from 30 / 6 ms^−2.
Option (c) is correct.
Explanation:
Initial force = 2 g = 20 N
Total mass = 5 + = 6 Kg
BC = 2 m
Initial acceleration = Force Mass=20 / 5 + 1=20 / 6 ms−2
Final force = (Load + mass of thread)×g
= (2+1) ×10=30 N
Therefore, final acceleration =30 / 6 ms^−2.
Thus the acceleration changes from 30 / 6 ms^−2.
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Answer:
(b)
Explanation:
Here mass of block A=5kg
Mass of 2m long uniform rope is 1kg
Therefore mass per unit length of rope=0.5kg/m
Mass of Block C =2kg
Therefore total mass of the system=5+2+1=8kg
When BC=0m then External Force acting on the system due to gravity =2g=20N
Therefore acc. of the system =20/8units
When BC=2m then total external force acting on the system due to gravity=(1+2)g=30N
Therefore acc. of the system=30/8units