Question

A trolley,while going down an inclined plane,has an acceleration of 2 cm s-².what will be it's velocity 3 s after the start?

Answer 1

Explanation:

plz Mark As Brainlist......

Answer 2

$\huge\star\sf\underline\pink{Solution :-}$

We have,

$\sf{Initial\: velocity (u) = 0} \\ \\ \sf{ Acceleration (a) = 2 \:cm\:s^{-2}} \\ \\ \sf{Time(t) = 3s}$

$\sf\underline\red{To\:Find:-} \\ \\ \\ \: \: \: \: \bullet\sf{ Final\: Velocity (v) =?} \\ \\ \\ \sf\underline\red{Formula\:used:}$

$\huge\orange{\boxed{\sf{ v = u + at}}}$

Now,

We have to enter the value to get desired data,

$\longrightarrow\sf{ v = 0 + 2 \times 3} \\ \\ \\ \longrightarrow\sf{v = 6\:cm\: s^{-1}}$

Thus,

The velocity of trolley after 3s will be 6 cm /s.

Extra Dose:

• IF a body starts from rest, its initial velocity (u) =0.

• If a body comes to rest (it stops) , its final velocity (v) = 0.

• If a body moves with uniform velocity , its acceleration (a) = 0.