a truck of mass 1800 kg is moving with velocity 54 km per hour and deaccelerates and comes to rest after travelling 200 m
find the the force applied by brakes and ud work done
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Answer:
m=1800 kg
u = 54 kmph = 15 m/s
v=0
s=200 m
a=v²-u²/2s
a=0-225/400
a=-0.5625m/s²
f=ma
f=1800*-0.5625
f=1012.5 N
w=fs
w=1012.5*200
w=202500 J
hope it helps u
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