a truck of mass is moved under a force .If the truck is then loaded with an object equal to the mass of truck and the driving force is halved ,then how does the acceleration change?
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wkt , a=F/m
1st case
a'=F/m
2nd case
a=(F/2)/2m= F/4m = 1/4 * F/m = 1/4*a'
therefore d acceleration becomes 1/4 times d previous value
1st case
a'=F/m
2nd case
a=(F/2)/2m= F/4m = 1/4 * F/m = 1/4*a'
therefore d acceleration becomes 1/4 times d previous value
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