Question

A tube 1 cm square in cross section is attached to the top of vessel 1 cm high and of cross section 100 cm square water is poured into the system feeling it to a depth of hundred centimetre about the bottom of the vessel . then find the force exerted by water against the bottom of the vessel.​

Answer 1

Hey mate,.

Simply multiply pressure with area

Pressure will be pgh , take h as 1m

and take area as 100 cm2in SI.

Hope it will help you.

✨sai

Answer 2

$\sf\huge{\underline{Question!}}$

A tube 1 cm square in cross section is attached to the top of vessel 1 cm high and of cross section 100 cm square water is poured into the system feeling it to a depth of hundred centimetre about the bottom of the vessel . then find the force exerted by water against the bottom of the vessel.

$\sf\bold{To\: find}$

Force exerted at the bottom of the container!

$\sf\huge{\boxed{\underline{Answer}}}$

According to the question!

we have ,,

p(density)= 1000kg\$m^{3}$

g = 10m/$s^{2}$

h =( 99 + 1)cm =100cm = 1m

then we have pressure!

P = $p\times g\times h$

= $1000\times 10\times 1$

=10000 N\m==(1)

we have,

pressure = $\frac{Force}{Area}$

➡ Force= $pressure\times area$==(2)

we have P = 10000N/m= $10^{4}$N/m

A = 100$cm^{2}$= $100\times 10^{-4}\times m^{2}$ = $10^{-2}\times m^{2}$

substituting in equation (2)

Force, F = $10^{4}\times 10^{-2}$

= $10^{4-2}$

= $10^2$ Newton

Therfore force exerted at the base of container by water is $10^2$ Newton..