A tube of length L is filled completely with an incompressible liquid of mass M and closed at both the ends.The tube is then rotated in a horizontal plane about one of it's ends with a uniform angular velocity £ .what is the force exerted by liquid at the other end ?
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The force exerted by liquid at the other end is the centripetal force due to rotation. The case can be treated as rotation of the center of mass of the liquid at distance L/2 from the axis of rotation.
Hence force exerted by liquid at the end =Mω
Mω^2( L/2) = 1/2 Mω^2L
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