Question

A tube of uniform cross section A is bent to form a circular arc of radius R forming three quarters of a circle. A liquid of density is forced through the tube with linear speed v. Find the net force exerted by the liquid on the tube.

Answer 1

Radius = R

density = rho

Area of cross section = A

speed = v

Now, see the attachment for solution.

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∆v = √2 v

t = 1.5πR/v

a = √2v^2 / 1.5πR

m = 1.5πpAR

F = √2pAv^2

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Answer 2

Answer:

F=√2pAv^2 is the net force exerted by the liquid on the tube