Question

A two-digit number exceeds the sum of the digits of that number by 18. If the digit at the units
place is double the digit in the tens place. what is the number?
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Answer 1

EXPLANATION.

Let the digit at tens place be = y

Let the digit at unit place be = 2x

=> 2x = y ........ (1)

A two digit number exceeds the sum of

the digit of the number by 18.

=> Let the number be = 10x + y

=> 10x + y = x + y + 18

=> 9x = 18

=> x = 2

Put the value of x = 2 in equation (1)

=> 2 X 2 = y

=> y = 4

Therefore,

original number = 10x + y = 10(2) + 4 = 24.

Answer 2

REFER TO THE ATTACHMENT

HOPE IT HELPS :)