a two digit number is such that the sum of its digits if 18 is added to the number 8 digit are reserved find the number
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Let the digit at units place be x and tens place be y.
∴ The two digit number = 10y + x.
Given, 10y + x = 4 (x + y)
=> 10y + x = 4(x + y)
=> 10y +x = 4x + 4 y
=> 10y - 4y = 4x - x
=> 6y = 3x
=> x = 2y
Also,
10y + x + 18 = 10x + y
=> 10y + x - 10x - y = -18
=> 9y - 9x = -18
=> 9(y - x) = -18
=> y - x = -2
=> y = -2 + x
=> y = -2 + 2y [x = 2y]
=> y - 2y = -2
=> -y = -2
=> y = 2
∴ x = 2y = 2 × 2 = 4
Thus, the number is 10 × 2 + 4 = 20 + 4 = 24
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∴ The two digit number = 10y + x.
Given, 10y + x = 4 (x + y)
=> 10y + x = 4(x + y)
=> 10y +x = 4x + 4 y
=> 10y - 4y = 4x - x
=> 6y = 3x
=> x = 2y
Also,
10y + x + 18 = 10x + y
=> 10y + x - 10x - y = -18
=> 9y - 9x = -18
=> 9(y - x) = -18
=> y - x = -2
=> y = -2 + x
=> y = -2 + 2y [x = 2y]
=> y - 2y = -2
=> -y = -2
=> y = 2
∴ x = 2y = 2 × 2 = 4
Thus, the number is 10 × 2 + 4 = 20 + 4 = 24
Thanks for the question!!
☺☺☺
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