A two-digit number is such that the sum of its digits is 4.if 18 is added to the number,its digits are reversed.find the other
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let \: the \: ones \: digit \: = x \\ and \: tens \: digit \: = y \\ so \: the \: number \: = 10y + x \\ according \: to \: question \: x + y = 8..........(1) \\ and \: if \: added \: 18 \: the \: number \: => 10y + x + 18 = 10x + y \\ = > 9y - 9x = - 18 \\ => 9x - 9y = 18..........(2) \\ (1) \times 9 => 9x + 9y = 72........(3) \\ (3) - (2) => 18y = 54 \\ so \: y = 3 \\ and \: from \: (1) \: x = 5 \\ hence \: the \: number \: is \: = 10y + x = 10 \times 3 + 5 = 35
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