Question

A uniform chain of mass M and length L has its one end at the top of a square and its potential energy with respect to centre of the square .​

Answer 1

Answer :

$\boxed{ \sf u = \frac{mgr}{ \theta} \sin( \theta). }$

Explanation :

See the attachment. .. .. .. .. .

Hence, it is solved.

Answer 2

Solution is attached above .....