Question

A uniform electric field of 30 N/C exists along the x axis. Calculate the potential difference Vb-Va between the points A (4m,2m) and B(10m,5m)​

Answer 1

Explanation:

the answer of ur question is solved in the above image

Answer 2

Concept:

Potential differences at any two points can be defined as the negative integral of the electric field with respect to the distance over the limits of the two points.

Given:

The uniform electric field of 30 N/C exists along the x-axis and the two points, A (4m,2m) and B (10m,5m)​.

Find:

The potential difference between the given points.

Solution:

As the electric field is given in the x-direction, the potential difference will be on the x-axis only.

So, the limits of the integrations will be the x-coordinates, from x = 4 to x = 10

V = - [Edr]¹⁰₄ = [-E r]¹⁰₄ = -30 N/C × (10 - 4)

V = - 180 V

Hence, the potential difference between the two points, A (4m,2m) and B (10m,5m)​ is - 180 V.

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