a uniform half metre rule can be balanced at the 29.0 cm mark when a mass 20g is hung from its one end .find the mass of the half metre rule
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Answered by
349
Hello Dear.
Here is the answer---
•¶ Refers to the attachment for the Question.
Let the weight of the half metre rule be x gf and it acts at the 25 cm mark (centre of gravity).
Now,
•Acticlockwise moment = x * 4
•Clockwise moment = 20 * 21
In equilibrium,
Anticlockwise moment = Clockwise moment
•4x = 20*21
x = 105 gf.
Thus, the weight of the metre rule is 105 gf.
•We know, one gf is the force acting on the body of mass 1 grams, thus mass of the body is 105 grams.
°°°°°°°°°°°=°°°°°°°°°°°°°
•Hope it helps.•
Have a Marvelous Day ☺️
Here is the answer---
•¶ Refers to the attachment for the Question.
Let the weight of the half metre rule be x gf and it acts at the 25 cm mark (centre of gravity).
Now,
•Acticlockwise moment = x * 4
•Clockwise moment = 20 * 21
In equilibrium,
Anticlockwise moment = Clockwise moment
•4x = 20*21
x = 105 gf.
Thus, the weight of the metre rule is 105 gf.
•We know, one gf is the force acting on the body of mass 1 grams, thus mass of the body is 105 grams.
°°°°°°°°°°°=°°°°°°°°°°°°°
•Hope it helps.•
Have a Marvelous Day ☺️
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127
hope it helps ...it s correct
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