A uniform ladder of length 10 metre and with 100 kg is kept with its lower end on smooth horizontal floor and the upper end on a smooth vertical wall horizontal string tied tied to the bottom of the ladder keep it in equilibrium find the tension along the string if a man weighing 60 kg goes up by 3 metre in the ladder which is inclined at 30 degree with horizontal .
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The tension in the string =39.631
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tnwramit1:
Ra X AC = W X BE
Ac/Ab=sin30 then ab is the length of ladder the ac i.e. height of wall is 5
Ac =5
Similarly BE = BH cos 30
BE=4.33
then put all the values in equ and u get AC
sorry Ra
and that is equal to Tension
this is simple method
the method used in pic is little complicated so try this
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