A uniform rod of length l and mass 2m rests on a smooth horizontal table
Answers
Answered by
1
Answer:
question is incomplete
Answered by
1
Answer:
Let us take the point of reference
as C which is the center of the
(rod & point mass) system
By linear momentum conservation,
mv=3mvcm
vcm=
3
v
I
C
= I (of rod about O) +2m(l/6)
2
+I (Point mass about C
=
12
2ml
2
+
36
2ml
2
+m(
6
2l
)
2
=
6
ml
2
+
18
ml
2
+
9
ml
2
=
3
ml
2
By angular momentum conservation about C,
mv
3
l
=Icw⇒mv
3
l
=
3
ml
2
w
∴
w=
l
v
→ ans.
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