Question

A uniform rod of mass m and length l is suspended by two strings at its ends as shown when one of the string is cut, the rod starts falling with an initial angular acceleration?

Answer 1

We can start answering this equation by using,

Torque (T) = Moment of Inertia (I) x Angular acceleration (α)

T = Iα ---------(1)

For this question,

I = (1/12)m$L^{2}$ ; (Use the Moment of Inertia of the rod from one end, not from the middle)

T = mg x (L/2)

We can substitute above results for equation (1),

mg x (L/2) = (1/12)m$L^{2}$ x α

α = 6g/L

α = (6 x 10)/L rad$s^{-1}$

α = 60/L rad$s^{-1}$

Answer 2

Answer:

refer to the attachment...

Explanation:

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