Physics, asked by sumitkash8742, 10 months ago

A uniform wooden stick of mass 1.6 kg and length ℓ rests in an inclined manner on a smooth, vertical wall
of height h (<ℓ) such that a small portion of the stick extends beyond the wall. The reaction force of the
wall on the stick is perpendicular to the stick. The stick makes an angle of 300
with the wall and the bottom of the stick is on a rough floor. The reaction of the wall on the stick is equal in magnitude to the reaction of
the floor on the stick. The ratio h/ℓ and the frictional force f at the bottom of the stick are
(g = 10 ms⁻²)
(A) h/ℓ = √3/16, ????= 16√3/3 N
(B) h/ℓ = 3/16, ????= 16√3/3 N
(C) h/ℓ = 3√3/16, ????= 8√3/3 N
(D) h/ℓ = 3√3/16, ????= 16√3/3 N

Answers

Answered by goyalsaumya29
1

Answer:

Hey can u pls ask the question clearly again didnt understand

Explanation:

I am not writing this whole thing for points

if i could understand ur Question I would love to HELP

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