A vector is represented by 3i+j+2k then what is the length in XY plane
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The given vector has components of 3, 1, respectively in the x and y directions.
To determine its length we require its projection in the x-y plane. For this the xand y components should be sufficient.
It’s magnitude or length in a given plane is determined by:
x2+y2−−−−−−√x2+y2
where x and y denote the x and y components respectively.
Plugging in the values, the output obtained is: 32+12−−−−−−√32+12 which is: 3.16227766017
To determine its length we require its projection in the x-y plane. For this the xand y components should be sufficient.
It’s magnitude or length in a given plane is determined by:
x2+y2−−−−−−√x2+y2
where x and y denote the x and y components respectively.
Plugging in the values, the output obtained is: 32+12−−−−−−√32+12 which is: 3.16227766017
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