Question

A vector of 10 units acts at a point making an angle 300 with the horizontal. What are

the horizontal and vertical components of the vector?​

Answer 1

Explanation:

As i understand ur question..

Let vector is a= 10 units

Angle =30°

$Horizontal \: \: \: component = a \cos(\theta) \\ \\ = 10 \cos(30) \\ \\ = 10 \times \frac{ \sqrt{3} }{2} \\ \\ = 5 \sqrt{3} \: \: \: units$

$Vertical \: \: \: component = a \sin(\theta) \\ = 10 \sin(30) \\ \\ = 10 \times \frac{1}{2} \\ \\ = 5 \: \: units$

Answer 2

We know

• Horizontal Component of Vector = vcos(θ)

• Vertical Component of Vector = vsin(θ)

According To Question

• v = 10

• θ = 30

Solution

Horizontal Component of Vector = vcos(θ)

⇒ Horizontal Component of Vector = 10 × cos(30)

⇒ Horizontal Component of Vector = 10 × √3/2 units

⇒ Horizontal Component of Vector = 5 × √3 units

⇒ Horizontal Component of Vector = 5√3 units

Vertical Component of Vector = vsin(θ)

⇒ Vertical Component of Vector = 10 × sin(30)

⇒ Vertical Component of Vector = 10 × 1/2 units

⇒ Vertical Component of Vector = 10/2 units

⇒ Vertical Component of Vector = 5 units