a vector of magnitude 5√3 units and another vector of magnitude 10 units are inclined to each other at 30° .the magnitude of vector product is
Answers
Answered by
0
R=√a^2+b^2+ 2abcos30
= √175+50√3*√3/2
=√250
=15.811
= √175+50√3*√3/2
=√250
=15.811
sanjay270899:
you have find resultant not vector product...
Answered by
6
let be two vectors name A and B
magnitude of vector A = 5√3
magnitude of vector B = 10
vector product of A & B
=(magnitude of vector A)(magnitude of vector)sin30°
=5√3 × 10 × (1/2)
=25√3...................................answer
magnitude of vector A = 5√3
magnitude of vector B = 10
vector product of A & B
=(magnitude of vector A)(magnitude of vector)sin30°
=5√3 × 10 × (1/2)
=25√3...................................answer
Similar questions