a vertical pillar stands on the plain
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#BAL
AB denotes the height of the tower BD the flagstaff and P the given point note that there are two right triangles PAB and PAD we are required to find the length of the flagstaff,DB and the distance of the building from the point P is PA
we have ,
tan60°=AB/AP
√3= 5/AP
AP=5√3
,the distance from the tower from P is 5√3m=8.66m(√3=1.732)
let us suppose DB=xm ,
AD=(5+x)m
now in right triangle PAD =tan45°=AD/AP=5+x/5√3
1=5+x/5√3
.., x=5(√3-1)
5×1.732-5 (√3=1.732)
= 8.66-5
=3.66
so, the height of the pillar is 3.66m
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