Question

a vertical pole 5 metre long Casts a shadow of length 2.4 meaterso the ground,then the heightof a tower which casts a shadow of length 12meaterat the same time is​

Answer 1

ANSWER--

let Ab be the vertical pole of 5m which cast a shadow of 2m on ground now Pq is another tower which cast a shadow of 25 m

therefore we have two triangle Abc And Pqr

in Δabc &Δpqr

angle abc= angle pqr(each 90)

angle bca=angleqrp(angle of elevation)

hence, Δabc~Δpqr(aa similarly)

ab/pq=bc/qr (sides propertionate)



pq= 25*5/2=62.5

pq 62.5 m

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