Question

a vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long . Find the height of the tower .​

Answer 1

⭐⭐HELLO MATE HERE IS YOUR ANSWER⭐⭐

☞As both the triangles are similar

by AA similarity

$\frac{height \: of \: pole}{height \: of \: building} = \frac{shadow \: of \: pole}{shadow \: of \: building \: }$

$= > \frac{6}{4} = \frac{x}{28} \\ = > \frac{6 \times 28}{4} \\ = > 6 \times 7 \\ = > 42$

Therefore height of tower (building) =42m

⭐⭐HOPE THIS HELPS YOU⭐⭐

⭐⭐FOLLOW ME FOR ANY OTHER QUESTIONS⭐⭐

Answer 2

Answer:

a vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long . Find the height of the tower .

Step-by-step explanation:

⭐⭐HELLO MATE HERE IS YOUR ANSWER⭐⭐

☞As both the triangles are similar

by AA similarity

\frac{height \: of \: pole}{height \: of \: building} = \frac{shadow \: of \: pole}{shadow \: of \: building \: }heightofbuildingheightofpole=shadowofbuildingshadowofpole

\begin{lgathered}= > \frac{6}{4} = \frac{x}{28} \\ = > \frac{6 \times 28}{4} \\ = > 6 \times 7 \\ = > 42\end{lgathered}=>46=28x=>46×28=>6×7=>42

Therefore height of tower (building) =42m

⭐⭐HOPE THIS HELPS YOU⭐⭐

⭐⭐FOLLOW ME FOR ANY OTHER QUESTIONS⭐⭐