A vertical pole of length 8m cast a shadow 6cm long on the ground at the same time a tower cast a shadow
30 cm long. Find the height of the tower
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Height of pole=AB=6 m
Length of shadow of pole =BC=4 m
Length of shadow of tower=EF=28 m
In △ABC and △DEF
∠B=∠E=90∘
both 90∘
as both are vertical to ground
∠C=∠F (same elevation in both the cases as both shadows are cast at the same time)
∴△ABC∼△DEF by AA similarity criterion
We know that if two triangles are similar, ratio of their sides are in proportion
So,
DE/AB = EF/BC
⇒ 6/DE = 28/4
⇒DE=6×7=42 m
Hence the height of the tower is 42 m.
hope it helps uh...
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