Question

A vessel contains water up to a height of 1.5 m. Taking the density of water 10^3 kg/m^3, acceleration due to gravity 9.8 m/s^2 and area of base of vessel 100 cm^2, calculate the pressue and the thrust, at the base of the vessel

Answer 1

Explanation:

static pressure exerted by water =

density*height*accln due to gravity

= (1000*1.5*10) = 15000 N/m^2

thrust = pressure*area= (15000*100*0.0001) = 150 newton

Answer 2

$\bold{(a) \: Pressure} \\ \bold{Height = 1.5m} \\ \bold{Density = 1000 kg/m³} \\ \bold{Acceleration \: due \: to \: gravity \: = \: 9.8m/s²} \\ \bold \green{Pressure \: = \: hpg} \\ \bold{ = \: 1.5 \times 1000 \times 9.8} \\ \bold{ = \: 14700 Pa} \\ \bold \red{ = \: 1.47 \times {10}^{4} N/m² \: \: ....ans}$

$\bold{(b) \: Thrust \: at \: the \: base \: of \: vessel} \\ \bold{Pressure \: = \: \frac{force}{area} } \\ \bold \green{force \: = \: Pressure \times area} \\ \bold{ = \: 1.47 \times {10}^{4} \times 100} \\ \bold \red{ = \: 147 N \: \: ....ans}$

Hope it helps you...

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