A vessel of 25 l capacity contains 10 mol of steam under 50 bar pressure. Calculate the temperature (in k) of steam using van der waals equation if for water:
Answers
Answered by
0
Answer:
hope it help for you and I solved it pls checked it
Attachments:
Answered by
0
Answer:
Given : A vessel of 25 litres capacity contains 10 moles of steam under pressure of 50.3 atm.
a= 5.46 bar L² mol¯² and b = 0.031 mol¯1.
To find : The temperature of steam using Van Dar Waals equation .
solution : Using gaseous formula for real gas,
here, P = 50.3 atm
V = 25 L
n = 10
a = 5.46 bar L² mol¯²
b = 0.031 mol¯¹
[50.3 + (5.46 × 10²)/25²][25 - 10 × 0.031] = 10 × 0.082 × T
⇒[50.3 + 546/625] [25 - 0.31] = 0.82T
⇒(50.3 + 0.8736)(24.69) = 0.82T
⇒(51.1736)(24.69) = 0.82T
⇒T = 1540.82461 ≈ 1531 K
Therefore temperature of steam using Van Dar Waals equation is 1531 K
Explanation:
Similar questions