Question

A vessel of volume 5 litre contains 1.4 g of nitrogen at a temperature 1800 K. The
pressure of the gas if 30% of its molecules are dissociated into atoms at this temperature
is :
(a) 4.05 atm
(b) 2.025 atm
(C) 3.84 atm
(d) 1.92 atm​

Answer 1

Answer:

N2⟺2N

Initial Moles of N2=1.428

Initial Mole of 2N = 0

Mole after dissociation of N2=1.428×70100

Moles after dissociation of 2N = 1.428×2×30100

Total Mole = 1.428×70100+1.4×60100×28

=1.428×[130100]

P×5=1.4×13028×100×0.0821×1800

P = 1.92 atm