Question

A vibrating stretched string resonates with a tuning fork of frequency 512 Hz when the length of the string is 0.5 m. The length of the string required to vibrate resonantly with a tuning fork of frequency 256 Hz ​

Answer 1

Answer:

1m

Explanation:

as we know that

Lf= lf

512× 0.5= 256×X

2×0.5= X

X= 1