Question

if the zeroes of the polynomial x^3-12x^2+39x-28 are a-b,a,a+b,find all the zeroes

Answer 1

Answer:

Step-by-step explanation:

Q:p(X)=x³-21x²+39x-28

The zeroes given are:

a-b,a,a+b

a-d+a+a+d=12.

3a=12

a=4

a(a+ b)(a-b)=28

a(a²-b²)=28

4(16-b²)=28

16-b²=7

-b²=-9

b=3

⏺a-b=1

⏺️a = 4

⏺️a+b=7

ANS:- The ZEROES are:-1,4,7