A volume of 1.1 liters of o2 was collected inside a balloon at 295 k and 13.6 psi. the next day, the surrounding conditions were observed to be 32°c and 0.98 atm. what is the volume of the gas inside the balloon? (1 atm = 14.7 psi)
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Number of Gaseous molecules are unchanged .
Then we should use the formula,
P denotes the pressure, V denotes the volume and T is the temperature.
Now, Given,
P₁ = 13.6psi = 13.6/14.7 atm [∵ 1 atm = 14.7 psi ] , P₂ = 0.98 atm
V₁ = 1.1 L , V₂ = ?
T₁ = 295 K , T₂ = 32 + 273 = 305K
∴ 13.6/14.7 × 1.1/295 = 0.98 × V₂/305
⇒ 13.6 × 11/14.7 × 295 = 0.98V₂/305
⇒ V₂ = 1.0736 L
Then we should use the formula,
P denotes the pressure, V denotes the volume and T is the temperature.
Now, Given,
P₁ = 13.6psi = 13.6/14.7 atm [∵ 1 atm = 14.7 psi ] , P₂ = 0.98 atm
V₁ = 1.1 L , V₂ = ?
T₁ = 295 K , T₂ = 32 + 273 = 305K
∴ 13.6/14.7 × 1.1/295 = 0.98 × V₂/305
⇒ 13.6 × 11/14.7 × 295 = 0.98V₂/305
⇒ V₂ = 1.0736 L
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