Question

A wall 9.68 M long and 6.2 M height is covered with rectangular tiles of size 44 CM by 20 cm find the total cost of the tiles at rupees 18.50 par tile

Answer 1

Answer:

Rs. 12,617

Step-by-step explanation:

Length of wall (L) = 9.68 m

Height (Breadth in this case) of Wall (B) = 6.2 m

Thus, area of wall (A) = LB = 9.68 * 6.2 = 60.016 m²

Now, Length of tile (l) = 44 cm = 0.44 m

Breadth of tile (b) = 20 cm = 0.2 m

Thus, Area of tile (a) = 0.44 * 0.2 = 0.088 m²

No. of tiles (n) = A/a = 60.016/0.088 = 682 tiles

Cost per tile (c) = Rs. 18.50

Thus, total cost = c*n = Rs. (18.5 * 682) = Rs. 12,617

Answer 2

given that,
the length of wall = 9.68m
the height of wall = 6.20m
now, area = 9.68x6.20=60.016m sq
area in cm=6001.6 cm sq
again,
length of a tile=44cm
breadth of a tile=20cm
area =44x20=880cm sq
number of tiles= area of wall/area of a tile
6001.6/880= 6.82
cost of a tile = 18.50
total cost = 18.50x6.82=126.17 rupees