Question

- A wall of length 10m was to be built across an open ground. The height of
the wall is 4m and thickness of the wall is 24cm. if this wall is to be built
up with bricks whose dimensions are 24cm x 12cm x 8cm. how many
bricks would be required.​

Answer 1

Step-by-step explanation:

here l=10M

b=4m

h = 0.24m

so volume of cuboid = l×b×h

therefore 10×4×0.24=9.6m

also volume of bricks l×b×h= 24×12×8=2304

bricks would be used for wall =area of bricks/area of wall

9.6/2304=240 bricks

Answer 2

$\:\:\:\dag\:{\underline{\underline{\mathfrak{\red{Given :-}}}}}$

$\:\:{\mathfrak{\purple{For \:wall}}} \begin{cases}{\sf{Length\: (l) = 10 m\: \Rightarrow\: 1000 cm}}\\{\sf{Height \:(h) = 4 m \: \Rightarrow\:400 cm}}\\{\sf{Breadth \:(b) = 24 cm}}\end{cases}$

$\:\:{\mathfrak{\purple{ For \:brick }}} \begin{cases}{\sf{Length \:(l) = 24 cm}}\\{\sf{Breadth \:(b) = 12 cm}}\\{\sf{Height\: (h) = 8 cm}}\end{cases}$

$\:\:\:\dag\:{\underline{\underline{\mathfrak{\orange{To \ Find:- }}}}}$

• $\sf{Number \ of \ bricks \ required}$

$\:\:\:\dag\:{\underline{\underline{\mathfrak{\blue{Solution :-}}}}}$

$\bigstar\:\:\rm{Volume \ of \ wall = \ } {\boxed{\sf{Length \times Breadth \times height}}}$

$\:\:\::\implies\:\:\sf{ 1000 \times 24 \times 400}$

$\:\:\::\implies\:\:\sf{ 1000 \times 9600}$

$\:\:\::\implies\:\:\sf{ 9600000 cm^3}$

$\bigstar\:\:\rm{Volume \ of \ brick = \ } {\boxed{\sf{Length \times Breadth \times height}}}$

$\:\:\::\implies\:\:\sf{ 24 \times 12 \times 8}$

$\:\:\::\implies\:\:\sf{ 24 \times 96}$

$\:\:\::\implies\:\:\sf{ 2304 cm^3}$

$\bigstar\:\:\rm{Number \ of \ bricks = \ } {\boxed{\bf{\dfrac{Volume\: of \:wall}{ Volume\: of\: brick}}}}$

$\:\:\::\implies\:\:\sf{ \dfrac{9600000 cm^3}{ 2304 cm^3}}$

$\:\:\::\implies\:\:\sf{\dfrac{ 9600000 }{2304}}$

$\:\:\::\implies\:\:{\boxed{\mathfrak{\pink{4166.6}}}}$