Question

a watch which gains uniformly was observed to be 6 minutes slow at 9:00 a.m. on Tuesday and 3 minutes fast at 12 noon of the subsequent Wednesday when did the watch show that correct time
please answer fast and with full explanation

Answer 1

Answer:

11.00 am

Step-by-step explanation:

Duration from 9.00 am to 12 noon

Duration = 3 hours = 180 mins

Find the extra minutes moved in that 3 hours:

Extra mins moved = 3 + 6 = 9 mins

The clock moved 9 mins extra in that 3 hours

3 hours = 9 mins extra

1 hour = 3 mins extra

So we add extra 3 mins after every hour

9.00 am ⇒ Showing 8:54 am

10.00 am  ⇒ Showing 9.57 am

11.00 am ⇒ Showing 11.00 am

12.00 pm ⇒ Showing 12.03 pm

Answer The time is correct at 11.00am

Answer 2

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