A well dug 20 m deep and it has a diameter 7 m. The earth which is so dug out is spread evenly on a rectangular plot 22 m long and 14 m broad. What is the height of platform formed?
Answers
Answered by
460
Lets 1st find the volume of the mud dug out. Formula used will be 
r²h.
Hence we have volume = 22/7 × (7/2)² × 20
We also have the volume of the cuboid at L x B x H
Here L = 22 and B = 14, we need to find H
Since the two volumes are equal, we have
22 x 14 x H = 22/7 × (7/2)² × 20
Hence we get the Height of the platform as 2.5m
Hence we have volume = 22/7 × (7/2)² × 20
We also have the volume of the cuboid at L x B x H
Here L = 22 and B = 14, we need to find H
Since the two volumes are equal, we have
22 x 14 x H = 22/7 × (7/2)² × 20
Hence we get the Height of the platform as 2.5m
Answered by
832
Solution:-
Diameter = 7 m so, radius = 3.5 m
H = 20 m
Volume of the earth dug out = π r² h
= 22/7 × 3.5 × 3.5 × 20
= 770 m³
Area of the platform = Length × breadth
⇒ 22 × 14 = 308 m²
Height of the platform = Volume of the earth dug out/area of the platform
⇒ 770/308
Height of the platform = 2.5 m Answer.
Diameter = 7 m so, radius = 3.5 m
H = 20 m
Volume of the earth dug out = π r² h
= 22/7 × 3.5 × 3.5 × 20
= 770 m³
Area of the platform = Length × breadth
⇒ 22 × 14 = 308 m²
Height of the platform = Volume of the earth dug out/area of the platform
⇒ 770/308
Height of the platform = 2.5 m Answer.
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